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PHYSICS OBJ:
1ABABDBBBBC
11CCCDADCABA
31ADBCDACBB

PHYSICS THEORY ANSWER
1.

(a) Horizontal speed just before it strikes floor = ucos(theta)

= 10cos0°

= 10 m/s
(b) t = √(2g/h)

= √(2*10*1)

= √20

= 4.47s

=============================
2

– medical uses

– welding and cutting

– military uses for defense and counter measures

================================
3.

Magnetic materials:

– Iron

– Cobalt

– Nickel

===============================
4.

(a) given: u = 20m/s

t = 4s

g = 10m/s²

h = ?

Using s = ut – ½gt²

s = 20(4) – ½(10)(4)²

s = 0m
(b) The inference is that after 4s, the ball returns back to the plane of projection

===============================
5.

The factors that determine the location of a solar power station are

– Intensity of sun light

– surface slope

– feeder capacity of the distribution center

===============================
8a)

i. Force is a push or pull which changes a body’s state of rest or uniform motion in a straight line.
ii.

a) field force

b) contact force
8b)

i. Bodies streamlined in

Shape move through fluid so as to oppose or overcome the motion of the fluid
ii.

a) fish

b) submarine
8c)

Mass= 1.3 kg

F= 1.2 m

V= 7.0 m/s
Drawing
ii. Acceleration

Note , V²= U² + 2as
Where S=r=1.2 m
(7.0)²= 0²+2× a (1.2)
= 49/2.4 = 2.4a/2.4
a = 20.4
B) Force=?

From force = MA

Force =1.3×20.4

Force =25.52

===============================
9)

(a) Poor conductors of heat application: – Coat (Trapped air in between the fabric)

– The hair and the fur of animals are bad conductors for heat and they protect them from cold .
(b)

Renewable: Water, corn stalk

Non-renewable: coal, natural gas
(c) A closed is a physical system so far removed from other systems that it does not interact with them.
d) heat required to melt = mc∆ + ml

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Note: Not sure of the temperature given, if it is -3°C or -5°C, However,

Using -3°C

Heat = (0.1×2200×3)+(0.1×2.26×10^6)

= 226660 J
e)

i. Given: 75 heart beats in 1 min

Therefore in 1 hour, we have (75×60) heart beats = 4500 heart beats

Also given: 2J of energy is expended in 1 heart beat

Therefore for 4500 heart beats, energy expended = (4500×2) J = 9000J
ii. Energy = mc∆

9000 = (0.25×4200×∆)

9000 = 1050∆

∆ = 9000/1050

Temperature rise = 8.57°C

================================

11)
(a)
– Electrical method

– Contact method
(b) Electric lines of force are imaginary lines drawn in an electric field in such a way that the direction at any point gives the direction of the electric field at such a point
(c) QR = SP
(d) Resistivity is the resistance of a unit length of material of unit cross-sectional area
d) heat required to melt = mc∆ + ml

Note: Not sure of the temperature given, if it is -3°C or -5°C, However, *Using -3°C*

Heat = (0.1×2200×3)+(0.1×2.26×10^6)

= 226660 J
(e) Given: F = 50Hz

L = 10 mH (10×10^-³H)

Inductive reactance, XL = 2πFL

= 2×3.14×50×10×10^-³

= 3..14 ohms
(f) If voltmeter reads 12V, over the 500 ohms, then using I = V/R

current in the circuit is I = 12/500

I = 0.024A

Hence over the 200 ohms, V = IR

V = 0.024×200

V = 4.8 VOLTS

Voltmeter will read 4.8 volts

PHYSICS ANSWERS

OBJ LOADING….

 

 

SECTION-A ANS 5 ONLY
================================
4a)
Time (t)=4secs
V=0ms^-1
pie call,V^2=U^2+2gh
O^2=20^2+2(-10)h
0=400-20h
20h/20=400/20
h=20m
4b)
the magnitude of the initial speed (u) is equal to the magnitude of
the height attained
================================
6)
A P-type seme-coductor is an extresic semi conductor which has
been diped with a trivalent impurity wheel holes are majority charge
carries and electron are the majority charge carries
2)
i)used ineye surgery
ii)used for the precise cutting of flat material
iii)used for measuring distances
================================
3)
i)iron
ii)steel
iii)nickel
================================
5)
i)availability of constant sunlight
ii)nearness to power grid
iii)must be closer to both skilled and unskilled labour
================================

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8ai)

Force is a push or pull which changes a body’s state of rest or uniform motion in a straight line.

II)a) field force
b) contact force
=================
8bi)
Bodies streamlined in
Shape move through fluid so as to oppose or overcome the motion of the fluid

II) a) fish
B) submarine
==================
8c)

Mass= 1.3 kg
F= 1.2 m
V= 7.0 m/s

Drawing

II) Acceleration
Note , V²= U² + 2as

Where S=r=1.2 m

(7.0)²= 0²+2× a (1.2)

= 49/2.4 = 2.4a/2.4

a = 20.4

B) Force=?
From force = MA
Force =1.3×20.4
Force =25.52

 

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